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Electric Flux & Gauss Law

Two point cha...

Question

Two point charges $Q_{1} = 10 μ C a n d Q_{2} = 20 μ C$ are placed at coordinates (1, 1, 0) and (-1, -1, 0) respectively. The total electric flux passing through a plane Z = 20 will be

7.5 μ C

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13.5 μ C

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15.0 μ C

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22.5 μ C

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Solution

The correct option is C $15.0 μ C$
Ans : (c)

Net electrical flux passing through plane Z = 20 i.e.

Half of the flux will bass through the plane at Z = 20 and the other half through the plane at Z = – 20

$Q = \frac{Q_{1} + Q_{2}}{2} = \frac{10 + 20}{2} = 15 μ C$

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