Two point charges q1 and q2 are located at -r1 and -r2 respectively in an external electric field -E-Total work done in assembling this configuration Eq1-q2- l-Type 1 for true and 0 for false

The net force due to charges is nbsp; F⃗=(q_1E+q_2E)r̂ Work done , W=F⃗.d⃗r⃗=E(q_1+q_2)r̂. δ lr̂=E(q_1+q_2)δ l ...

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Standard XII

Physics

Charging by Friction

Two point cha...

Question

Two point charges $q_{1}$ and $q_{2}$ are located at $_{1}$ and $_{2}$ respectively in an external electric field $\to E$ .Total work done in assembling this configuration $\frac{E (q_{1} + q_{2})}{δ l}$ .Type 1 for true and 0 for false

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Solution

The net force due to charges is $\to F = (q_{1} E + q_{2} E)^r$
Work done , $W = \to F . \to d r = E (q_{1} + q_{2})^r . δ l^r = E (q_{1} + q_{2}) δ l$

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Two point charges q1 and q2 are located at →r1 and →r2 respectively in an external electric field →E.Total work done in assembling this configuration E(q1+q2)δl.Type 1 for true and 0 for false

The net force due to charges is →F=(q1E+q2E)^rWork done , W=→F.→dr=E(q1+q2)^r.δl^r=E(q1+q2)δl

Two point charges $q_{1}$ and $q_{2}$ are located at $_{1}$ and $_{2}$ respectively in an external electric field $\to E$ .Total work done in assembling this configuration $\frac{E (q_{1} + q_{2})}{δ l}$ .Type 1 for true and 0 for false

The net force due to charges is $\to F = (q_{1} E + q_{2} E)^r$
Work done , $W = \to F . \to d r = E (q_{1} + q_{2})^r . δ l^r = E (q_{1} + q_{2}) δ l$