Two point charges $q_{A} = 3 μ C$ and $q_{B} = - 3 μ C$ are located 20 cm apart in vacuum. What is the electric field at the midpoint O of the line AB joining the two charges?

1.2 \times 10^{6} N / C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.4 \times 10^{6} N / C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6.9 \times 10^{6} N / C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9.9 \times 10^{6} N / C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $5.4 \times 10^{6} N / C$
Apply formula for electric field and superposition principle to get,
$E_{0} = 2 (\frac{k q}{(r)^{2}}) = 2 (\frac{3 \times 9 \times 10^{9}}{(0.1)^{2}}) = 5.4 \times 10^{6} N / C$

Suggest Corrections

Similar questions

Q. Two point charges

q_{A} = 3 μ c a n d q_{B} = - 3 μ c

are located 20 cm apart in vaccum. What is the electric field at the midpoint of the line joining the two charges.

Two point charges $q_{A} = 3 μ C$ and $q_{B} = - 3 μ C$ are located 20 cm apart in vacuum. What is the electric field at the midpoint O of the line AB joining the two charges?

If a negative test charge of magnitude $1.5 \times 10^{- 9} C$ is placed at this point, what is the force experienced by the test charge?

A non-conducting square sheet of side 10 m is charged with a uniform surface charge density, $σ = - 60 \frac{μ C}{m^{2}}$ . Find the magnitude and orientation of electric field vector due to the sheet at a point which is d = 0.02 mm away from the midpoint of the sheet.

Two point charges QA = 2 μ C and QA = -2 μC located 16 cm apart in vacuum. What is the electric field at the mid point O of the line AB joining the two charges?

Q. Two point charges

+ 3 μ C

and

- 3 μ C

are kept

20 c m

apart in air. Find the electric field midway between the charges on the line joining them. What will be the force experienced by a charge

+ 1.5 \times 10^{- 9} C

placed at this point ?

Join BYJU'S Learning Program

Two point charges qA=3μC and qB=−3μC are located 20 cm apart in vacuum. What is the electric field at the midpoint O of the line AB joining the two charges?

The correct option is B 5.4×106N/CApply formula for electric field and superposition principle to get, E0=2(kq(r)2)=2(3×9×109(0.1)2)=5.4×106N/C

Two point charges $q_{A} = 3 μ C$ and $q_{B} = - 3 μ C$ are located 20 cm apart in vacuum. What is the electric field at the midpoint O of the line AB joining the two charges?

The correct option is B $5.4 \times 10^{6} N / C$
Apply formula for electric field and superposition principle to get,
$E_{0} = 2 (\frac{k q}{(r)^{2}}) = 2 (\frac{3 \times 9 \times 10^{9}}{(0.1)^{2}}) = 5.4 \times 10^{6} N / C$