The correct option is A Stable
Here, two point charges +q and +q are fixed at (a,0,0) and (−a,0,0) and a third point charge q is at origin. Thus they form a stable equilibrium, since both the positive charges are separated by equal distance from −q charge, the forces due to both +q charges will be equal and balance to each other.
Now, if the charge −q is displaced along y-axis, the forces between charges will change. The horizontal component of the forces will balance each other while the vertical components will add each other and act downward which brings −q in equilibrium. Hence, the charges will in equilibrium for vertical displacement.