Two point charges $+ q$ and $- q$ are placed at points $A$ and $B$ respectively separated by a small distance. The electric field intensity at the midpoint $O$ of $A B$

Is zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Acts along

A B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Acts along

B A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Acts perpendicular to

A B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Acts along $A B$
Electric field due to $+ q$ is $E_{1} = \frac{k q}{(\frac{d}{2})^{2}}$ directed along $A B$
Electric field due to $- q$ is $E_{2} = \frac{k q}{(\frac{d}{2})^{2}}$ directed along $A B$
Total electric field $= E_{1} + E_{2} = 2 \frac{k q}{(\frac{d}{2})^{2}}$ along $A B$

Suggest Corrections

Similar questions

Q. Two charges

10 μ C

and

- 10 μ C

are placed at points

A

and

B

separated by a distance of

10 c m

.Find the electric field at a point

P

on the perpendicular bisector of

A B

at a distance of

12 c m

from its middle point

Q. Point charges

+ q, + q, - q

and

- q

are placed at the corners A, B, C and D respectively of a square. O is the point of intersection of the diagonals AC and BD. The resultant electric field intensity at the point O.

Two equal charges $‘ q^{'}$ of opposite sign are separated by a small distance $‘ d^{'}$ . The electric intensity $‘ E^{'}$ at a point on the straight line passing through the two charges at a very large distance $‘ r^{'}$ from the midpoint of two charges is :

Two electric charges $Q$ and $4 Q$ are separated by a certain distance. If the electric field intensity at $Q$ is E, the electric field intensity at the other charge is :