Two point like charges having magnitude -16 - C and -9 - C are separated by a distance 10 cm in air- The resultant electric field will be zero-

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Coulomb's Law - Vector Form

two point lik...

Question

two point like charges having magnitude $+ 16 μ C$ and $- 9 μ C$ are separated by a distance $10 c m$ in air. The resultant electric field will be zero.

30 cm

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20 cm

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10 cm

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4 cm

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Solution

The correct option is B 30 cm
To find equilibrium point where field is Zero.
Use;
$x = \frac{\sqrt{θ_{1}} \times r}{\sqrt{θ_{1}} \pm \sqrt{2 v}}$
[take $θ_{1}$ from which distance is calculate]
(+ use when Both charge is like, (-) use when unlike charge
$x = \frac{\sqrt{9}}{\sqrt{16} - \sqrt{9}} \times 10$ cm

$x = \frac{3}{4 - 3} \times 10 = 30 c m$

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two point like charges having magnitude +16μC and −9μC are separated by a distance 10cm in air. The resultant electric field will be zero.

The correct option is B 30 cmTo find equilibrium point where field is Zero.Use;x=√θ1×r√θ1±√2v [take θ1 from which distance is calculate](+ use when Both charge is like, (-) use when unlike chargex=√9√16−√9×10cmx=34−3×10=30cm

two point like charges having magnitude $+ 16 μ C$ and $- 9 μ C$ are separated by a distance $10 c m$ in air. The resultant electric field will be zero.