Question

Two point loads 40 kN and 60 kN distanced 6 m apart cross a girder of 16 m span with 40 kN load leading from left to right. Find the maximum BM.

• A. 289 kN-m
• B. 340 kN-m
• C. 460 kN-m
• D. 240.25 kN-m

Answer 1

The correct option is A 289 kN-m



$\overline{x}=\frac{40\times 0+60\times 6}{40+60}$

$\overline{x}=3.6m$





$+R_A\times 16-60\times 9.2-40\times 3.2=0$
$R_A=42.5$

BM under 60 kN = 42.5 x 6.8
= 289 kN-m