Two point masses of $0.3 k g$ and $0.7 k g$ are fixed at the ends of a rod of length $1.4 m$ and of negligible mass. The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. The point on the rod through which the axis should pass in order that the work required for rotation of the rod is minimum, is located at a distance of

0.42 m

from mass of

0.3 k g

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0.70 m

from mass of

0.7 k g

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0.98 m

from mass of

0.3 k g

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0.98 m

from mass of

0.7 k g

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Solution

The correct option is C $0.98 m$ from mass of $0.3 k g$
$w_{w / x}$ when axis is passing through centre of mass.
$\begin{matrix} i . e . x = \frac{0.3 \times 0 + 0.7 \times 1.4}{0.3 + 0.7} = 0.98 m f r o m 0.3 k g . A n s . (C) \end{matrix}$

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The correct option is C 0.98m from mass of 0.3kgww/x when axis is passing through centre of mass.i.e.x=0.3×0+0.7×1.40.3+0.7=0.98mfrom0.3kg.Ans.(C)

The correct option is C $0.98 m$ from mass of $0.3 k g$
$w_{w / x}$ when axis is passing through centre of mass.
$\begin{matrix} i . e . x = \frac{0.3 \times 0 + 0.7 \times 1.4}{0.3 + 0.7} = 0.98 m f r o m 0.3 k g . A n s . (C) \end{matrix}$