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Question

Two point masses of 0.3kg and 0.7kg are fixed at the ends of a rod of length 1.4m and of negligible mass. The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. The point on the rod through which the axis should pass in order that the work required for rotation of the rod is minimum is located at a distance of

A
0.42m from the mass of 0.3kg
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B
0.70m from the mass of 0.7kg
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C
0.98m from the mass of 0.3kg
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D
0.98m from the mass of 0.7kg
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Solution

The correct option is C 0.98m from the mass of 0.3kg
Work-energy theorem, Wallforces=12Iw2
Given: w is constant
So required work done to be minimum implies that I must be minimum.
Let the rotational axis passes through O.
I=0.3(x2)+0.7(1.4x)2
For I to be minimum, dIdx=0
0.3×2(x)0.7×2(1.4x)=0
x=0.98m


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