Two point masses of mass 4m and m respectively separated by distance d are revolving under mutual force of attraction. Ratio of their kinetic energies will be

1:4

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1:5

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1:1

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Solution

The correct option is A 1:4
$\frac{K_{A}}{K_{B}} = \frac{\frac{1}{2} I_{A} ω^{2}}{\frac{1}{2} I_{B} ω^{2}} I_{A} = 4 m (d / 5)^{2} I_{B} = m (4 d / 5)^{2} \frac{K_{A}}{K_{B}} = \frac{1}{4}$

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Two point masses of mass 4m and m respectively separated by distance d are revolving under mutual force of attraction. Ratio of their kinetic energies will be

The correct option is A 1:4KAKB=12IAω212IBω2IA=4m(d/5)2IB=m(4d/5)2KAKB=14

The correct option is A 1:4
$\frac{K_{A}}{K_{B}} = \frac{\frac{1}{2} I_{A} ω^{2}}{\frac{1}{2} I_{B} ω^{2}} I_{A} = 4 m (d / 5)^{2} I_{B} = m (4 d / 5)^{2} \frac{K_{A}}{K_{B}} = \frac{1}{4}$