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Question

Two point size bodies of same mass are knotted to a horizontal string one at the end, and the other at the mid point of it. The string is rotated in horizontal plane with the other end as centre. If T is tension in the string between centre of circles and first body then the tension in the string between the two bodies is

A
T2
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B
2T
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C
2T3
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D
3T2
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Solution

The correct option is C 2T3
Let T' is tension in outer string and T is tension in inner string.
Now, from FBD of outer mass,
T=m2Lω2
From FBD of inner mass,
TT=mLω2
T=3mLω2
T/T=2/3
T=2T/3
Option C is correct.

829279_698076_ans_d9b426414acf42ccadf8c418cafa21b8.PNG

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