Two point white dots are 1mm apart on a black paper. The are viewed by the eye of pupil diameter 3mm. Approximately, the minimum distance(in mt at which these dots can be resolved by the eye is Take wavelength to be 500nm
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Solution
We know, sinθdark =λa sinθ=1.22λD As θ is small we can write it as θ=1.22λD From diagram, 1×10−3x=1.22×500×10−93×10−3 x=10−3×3×10−31.22×500×10−9=5m