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Question

Two point white dots are 1 mm apart on a black paper. The are viewed by the eye of pupil diameter 3 mm. Approximately, the minimum distance(in mt at which these dots can be resolved by the eye is
Take wavelength to be 500 nm

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Solution

We know,
sinθdark =λa
sinθ=1.22λD
As θ is small we can write it as
θ=1.22λD From diagram,
1×103x=1.22×500×1093×103
x=103×3×1031.22×500×109=5 m


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