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Question

Two points A and B are located at distance of 100 cm from on electric dipole. A is sn axial point while B is in perpendicular bisector. The electric field intensity at A is E. Then the intensity at B will be

A
E
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B
2E
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C
E
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D
E2
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Solution

The correct option is D E2
Two points A and B are located at distance =100cm=100×102m
The electric field intensity at A=¯¯¯¯E
Then, the intensity at B will be
E1FEAEB=10050
EB=12EA

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