Two points A and B equidistant from the centre of a small bar magnet. Point ‘A’ is on the axial line and point ‘B’ is on the equatorial line. Then the magnetic fields at point ‘A’ and ‘B’ are in the ratio of

2 : 1

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1 : 2

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1 : 1

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1 : 4

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Solution

The correct option is D 2 : 1
$B A = \frac{2 μ_{0} m}{4 π d^{3}}$
$B_{B} = \frac{μ_{0} m}{4 π d^{3}}$
$\frac{B_{A}}{B_{B}} = 2 : 1$

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Two points A and B equidistant from the centre of a small bar magnet. Point ‘A’ is on the axial line and point ‘B’ is on the equatorial line. Then the magnetic fields at point ‘A’ and ‘B’ are in the ratio of

The correct option is D 2 : 1BA=2μ0m4πd3 BB=μ0m4πd3BABB=2:1

The correct option is D 2 : 1
$B A = \frac{2 μ_{0} m}{4 π d^{3}}$
$B_{B} = \frac{μ_{0} m}{4 π d^{3}}$
$\frac{B_{A}}{B_{B}} = 2 : 1$