Question

Two points $P$ and $Q$ are maintained at the potential of $10V$ and $-4V$ respectively. The work done in moving $100$ electrons from $P$ to $Q$ is:

• A. $-19\times {10}^{-7}J$
• B. $9.60\times {10}^{-17}J$
• C. $-2.24\times {10}^{-16}J$
• D. $2.24\times {10}^{-16}J$

Answer 1

Answer: (C)

$-2.24\times {10}^{-16}J$

$where,$

$n=numberofelectron$

$q=ne=100\times 1.6\times {10}^{-16}C$

$\Delta V=potentialdifference$

$W=100\times 1.6\times {10}^{-19}\times (-4-10)$

$W=-2.24\times {10}^{-16}J$

Hence, work done is $-2.24\times {10}^{-16}J$