Two poles,18m and 13m high,stand upright in a playground. If their feet are 12m apart find the distance between the poles

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Solution

Ab= 18 m
cd= 13 m
bd= 12 m
find ac
construction = draw a line ce parallel to bd
it means ebcd is rectangle
then ec = 12 m
angle aec= 90
ea =ab-eb
=18 m - 13 m
= 5 m
ea =5 m
ea^2+ec^2=ac^2
(5m)^2+(12m)^2=ac^2
(25+144)m^2=ac^2
ac^2=169m^2
square rooting both side
ac=13m

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Two poles,18m and 13m high,stand upright in a playground. If their feet are 12m apart find the distance between the poles

Ab= 18 m cd= 13 m bd= 12 m find ac construction = draw a line ce parallel to bd it means ebcd is rectangle then ec = 12 m angle aec= 90 ea =ab-eb =18 m - 13 m = 5 m ea =5 m ea^2+ec^2=ac^2 (5m)^2+(12m)^2=ac^2 (25+144)m^2=ac^2 ac^2=169m^2 square rooting both side ac=13m

Ab= 18 m
cd= 13 m
bd= 12 m
find ac
construction = draw a line ce parallel to bd
it means ebcd is rectangle
then ec = 12 m
angle aec= 90
ea =ab-eb
=18 m - 13 m
= 5 m
ea =5 m
ea^2+ec^2=ac^2
(5m)^2+(12m)^2=ac^2
(25+144)m^2=ac^2
ac^2=169m^2
square rooting both side
ac=13m