Two poles of equal heights are standing opposite each other on either side of the road which is 80 m wide. From the points between them on the road, the elevation of the top of the poles are 60∘ and 30∘ respectively. Find the height of the poles.
In ΔDPC
tanp=CDCP
tan300
1√3=CDCP
CP=CP√3 (1)
IN ΔAPB
tanp=ABPB
tan600=ABBP
√3BP=AB
CD=√3BP (2)
FROM (1) & (2)
CP√3=√3BP
CP=3BP
NOW ,BC=BP+CP
80=BP+3BP
BP=20m
CP=60m
CD=√3BP
=20√3