Two poles of height 10 m and 18 m stand on a plane ground. If the distance between the feet of the poles is 15 m, find the distance between the top of the poles.
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Solution
Let CD and AB be the poles of height 18 m and 10 m.
Therefore, CP = (18 - 10) m = 8 m
From the figure, it can be observed that AP = 15 m
Applying Pythagoras theorem in ΔAPC, we get AC2=PC2+AP2 AC2=82+152 AC2=(64+225)=289 AC=√289 AC=17m
Therefore, the distance between the top of the poles is 17 m.