Two poles of height 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between the top of the poles.
13m
Let CD and AB be the poles of height 11 m and 6 m.
Therefore, CP = (11 - 6) m = 5 m
from the figure, it can be observed that AP = 12 m
Applying Pythagoras theorem for ΔAPC, we get
AC2=PC2+AP2
(AC)2=(12)2+(5)2
AC2=(144+25)2=1692
AC = 13 m
Therefore, the distance between the top of the poles is 13 m.