Two poles of height 6m and 11m stand vertically upright on a plane ground. If the distance between their feet is 12m, the distance between their tops is:
A
12m
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B
14m
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C
13m
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D
11m
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Solution
The correct option is C13m Let AB and CD be two poles such that AB=6m and CD=11m. Given, AC=12m Now, ABEC is a rectangle, thus CE=6m,ED=5m and BE=12m Now, BED is a right angled triangle Hence, by Pythagoras theorem: BD2=DE2+BE2 BD2=122+52 BD=13m.