Two poles of heights $3$ m and $18$ m are standing on a plane ground. If the distance between the feet of the poles is $36$ m, find the distance between their tops.

29 m

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49 m

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39 m

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38 m

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Solution

The correct option is C $39 m$
$I n △ A K M :$
$A K = A B - M D = 18 - 3 = 15$
${A K}^{2} + {K M}^{2} = {A M}^{2} (p y t h a g o r a s t h m)$
$⟹ 15^{2} + 36^{2} = {A M}^{2}$
$⟹ {A M}^{2} = 36^{2} + 15^{2} = 1296 + 225 = 1521$
$⟹ A M = \sqrt{1521} = 39 m$
$∴ D i s t a n e b e t w e e n t o p s = 39 m$

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Two poles of heights 3m and 18m are standing on a plane ground. If the distance between the feet of the poles is 36m, find the distance between their tops.

The correct option is C 39mIn△AKM:AK=AB−MD=18−3=15AK2+KM2=AM2(pythagorasthm)⟹152+362=AM2⟹AM2=362+152=1296+225=1521⟹AM=√1521=39m∴Distanebetweentops=39m

Two poles of heights $3$ m and $18$ m are standing on a plane ground. If the distance between the feet of the poles is $36$ m, find the distance between their tops.