Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, then find the distance between their tops.
Let CD and AB be the poles of height 11 m and 6 m.
Therefore, CP = 11 - 6 = 5 m
From the figure, it can be observed that AP = 12m
Applying Pythagoras theorem for ΔAPC, we get
AP2+PC2=AC2
(12m)2+(5m)2=(AC)2
AC2=(144+25)m2=169m2
AC = 13m
Therefore, the distance between their tops is 13 m.