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Question

Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, then find the distance between their tops.

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Solution


Let CD and AB be the poles of height 11 m and 6 m.
Therefore, CP = 11 - 6 = 5 m
From the figure, it can be observed that AP = 12m
Applying Pythagoras theorem for ΔAPC, we get

AP2+PC2=AC2
(12m)2+(5m)2=(AC)2
AC2=(144+25)m2=169m2
AC = 13m
Therefore, the distance between their tops is 13 m.


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