Question

Two poles of heights 6 m and 11 m stand vertically on a plane pound. If the distance between their feet is 12 m. Then determine the distance between their tops.

• A. 11 m
• B. 13 m
• C. 12 m
• D. 9 m

Answer 1

The correct option is B 13 m

Let the two poles be $AC$ and $DE$ of height $6m$ and $11m$ respectively.

Distance between the feet of two poles is $\left(DC\right)=12m$

$AC=BD=6m$

$BE=DE-BD=11-6=5$ m

To find $AE$

Now, $\angle ABE={90}^o$

According to Pythagoras theorem

$(AE{)}^2=(AB{)}^2+(BE{)}^2$

$(AE{)}^2=(12{)}^2+(5{)}^2=144+25=169$

$AE=13$