Question

Two poles of heights 8 m and 15 m stand vertically on a plane ground. If the distance between their feet is 24 m, then find the distance between their top ends.

Answer 1

Let CD and AB be the poles of height 15 m and 8 m.
Therefore, CP = (15 - 8) m = 7 m
From the figure, it can be observed that AP = 24 m.
Applying Pythagoras' theorem for $\Delta APC,$ we get
$A{C}^2=P{C}^2+A{P}^2.$
$A{C}^2=7^2+{24}^2$
$A{C}^2=49+576=625m^2$
AC = 25 m
Therefore, the distance between the top ends of the poles is 25 m.