wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two positive numbers x and y are such that x>y. If the difference of these numbers is 5 and their product is 24, find sum of these numbers.

A
16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
19
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 11
Given,
x>y
Thus, xy=5 and xy=24
xy=5
Squaring both sides,
=>(xy)2=52
=>x2+y22xy=25
=>x2+y2=25+2(24)
=>x2+y2=73
Now,
(x+y)2=x2+y2+2xy
=73+2(24)
=73+48
=121
=>x+y=121
=±11
Given,
x and y are positive numbers,
Therefore,
x+y=11

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Formation of Algebraic Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon