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Question

Two possitively charged spheres of masses m1, and m2, are suspended from a common point at the ceiling by identical insulating mass-less strings of length I. Charges on the two spheres are q1 and q2, respectively. At equilibrium both strings make the same angle θ with the vertical. Then :

A
q1m1=q2m2
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B
m1=m2
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C
m1=m2sinθ
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D
q2m1=q1m2
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Solution

The correct option is B m1=m2
For equilibrium of m1
T1cosθ=m1g; T1sinθ=F
tanθ=Fm1g
For equilibrium of m2
T2cosθ=m2g; T2sinθ=F
tanθ=Fm2g
Thus comparing 2 equations m1=m2
677354_631501_ans_83e9272fc688486eaa4034335e2e0913.png

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