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Question

# Two prisms A and B have dispersive powers of 0.012 and 0.018 respectively. The two prisms are in contact with each other. The prism A produces a mean deviation of 1.2∘, then the mean deviation produced by B if the combination produces deviation without dispersion is

A
3.6
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B
0.8
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C
0.4
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D
1.8
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Solution

## The correct option is B 0.8∘We have the dispresive powers of the prisms as wA=0.012 wB=0.018 Also, the mean deviation produced by prism A is dA=1.2 We have to determine mean deviation produed by prism B, i.e. dB We know that Dispersive power=Angular DispersionMean deviation wA=θAdA wB=θBdB For deviation without dispersion difference in angular dispersion for the two prisms will be zero. θA−θB=0 θA=θB ⇒wAdA=wBdB 0.012×1.2=0.018×dB dB=1.2×1218=0.8∘

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