Question

Two progressive waves each of frequency $10Hz$ travelling at $20cm{s}^{-1}$ are superposed. In the resulting stationary wave, the distance between the successive nodes is

• A. $1cm$
• B. $2cm$
• C. $0.5cm$
• D. $0$

Answer 1

The correct option is A $1cm$

$f=\frac{\nu }{\lambda }$
$\lambda =\frac{\nu }{f}$
$=\frac{20}{10}$
$=2cm$
Distance between 2 successive nodes $\frac{\lambda }{2}$
$=\frac{2}{2}$
$=1cm$