Two projectiles each of mass m are projected with same velocity v making an angle α and β from the same point in opposite directions. Find the change in their momentum at any instant :
A
2mvsin(α+β)
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B
2mvsinα+β2
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C
2mvcos(α+β)
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D
2mvcosα+β2
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Solution
The correct option is D2mvcosα+β2 Horizontal change in momentum Δpx=m[vcosα−(−vcosβ)]
Vertical change in momentum Δpy=m[vsinα−gt−(vsinβ−gt)]
Net change in momentum Δp=√Δp2x+Δp2y =mv√(cosα+cosβ)2+(sinα−sinβ)2