wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two pulley arrangements of figure given are identical. The mass of the rope in negligible. In fig(a), the mass m is lifted by attaching a mass 2m to the other end of the rope. In fig(b), m is lifted up by pulling the other end of the rope with a constant downward force F=2mg. The acceleration of m in the two cases are respectively

A
3g, g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
g3,g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
g3,2g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
g,g3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B g3,g
Let a and a' be the acceleration in both cases respectivlely. Then for fig (a),

Tmg=ma....(i)
and 2mgT=2ma...(ii)
Adding (i) and (ii), we get
mg=3ma
a=g3
For fig (b),

Tmg=ma......(iii)
and 2mgT=0...(iv)
Solving (iii) and (iv)
a=g
a=g3 and a=g

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What's with All the Tension in the Room?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon