Two pure breeds of pea plant, one with yellow colour seeds (Y) and other with green colour seeds (y) are crossed to obtain F1 generation. The genotypic ratio for the resulting F2 generation will be:
A
3:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:3:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1:2:1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
9:3:3:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 1:2:1 ∙ Genotype of parents wil be YY and yy since they are pure breeds (homozygous). ∙ The F1 generation will have all heterozygous progenies (Yy). ∙ Upon self pollination, in F2 generation, the possible genotypes of seeds will be:
YY (1) - Homozygous yellow
Yy (2) - Heterozygous yellow
yy (1) - Homozygous green
Therefore, the genotypic ratio of F2generation will be 1:2:1.