Two putty balls of equal masses moving with equal speeds in mutually perpendicular direction, stick together after collision. If the balls were initially moving with a speed of $45 \sqrt{2} m s^{- 1}$ each, the speed of their combined mass after collision is.

45 \sqrt{2} m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

45 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

90 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

22.5 \sqrt{2} m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $45 m s^{- 1}$

Initial momentum

$\to P = m 45 \sqrt{2}^i + m 45 \sqrt{2}^j \Rightarrow | \to P | = m \times 90$

Final momentum = 2mV

By conservation of momentum $2 m \times V = m \times 90$

$∴$ V = 45 m/s

Suggest Corrections

Similar questions

Two putty balls of equal masses moving with equal velocity in mutually perpendicular directions, stick together after collision. If the balls were initially moving with a velocity of $45 \sqrt{2} m s^{- 1}$ each, the velocity of their combined mass after collision is

Two putty balls of equal mass moving with equal velocity in mutually perpendicular directions, stick together after collision. If the balls were initially moving with a velocity of $45 \sqrt{2} m s^{- 1}$ each, the velocity of their combined mass after collision is

Q. Two putty balls of equal masses moving in mutually perpendicular directions with equal speed, stick together after collision. if the balls were initially moving with a velocity of

45 \sqrt{2} m / s

each, find the velocity of the combined mass after collision.

Q. Two putty balls of equal masses moving with equal speeds in mutually perpendicular direction, stick together after collision. If the balls were initially moving with a speed of

45 \sqrt{2} m s^{- 1}

each, the speed of their combined mass after collision is.

Join BYJU'S Learning Program

Two putty balls of equal masses moving with equal speeds in mutually perpendicular direction, stick together after collision. If the balls were initially moving with a speed of 45√2 ms−1 each, the speed of their combined mass after collision is.

The correct option is B 45 ms−1 Initial momentum →P=m45√2^i+m45√2^j⇒|→P|=m×90 Final momentum = 2mV By conservation of momentum 2m×V=m×90 ∴ V = 45 m/s

Two putty balls of equal masses moving with equal speeds in mutually perpendicular direction, stick together after collision. If the balls were initially moving with a speed of $45 \sqrt{2} m s^{- 1}$ each, the speed of their combined mass after collision is.

The correct option is B $45 m s^{- 1}$

Initial momentum

$\to P = m 45 \sqrt{2}^i + m 45 \sqrt{2}^j \Rightarrow | \to P | = m \times 90$

Final momentum = 2mV

By conservation of momentum $2 m \times V = m \times 90$

$∴$ V = 45 m/s