The correct option is A Imaginary Roots
Given : px2−2qx+p=0...(i); qx2−2px+q=0...(ii);
Roots of (i) are real and unequal.
On comparing with standard form of quadratic equation 0=ax2+bx+c
We get, a1=p,b1=−2q,c1=p and a2=q,b2=−2p,c2=q
Let D1,D2 be the respective discrimanant values.
Where D1=(−2q)2−4.p.p = 4(q2−p2)
As the roots of (i) are real and unequal therefore the discriminant of (i) must be greater than zero.
∴D1=4(q2−p2)>0
⇒p2−q2<0...(iii)
And
⇒D2=(−2p)2−4.q.q = 4(p2−q2)
From (iii) we come to know that D2 is always less than zero, therefore the roots of the equation (ii) are imaginary.