Two radio active elements X and Y have half lives of 50 minutes and 100 minutes respectively. Samples of X and Y initially contain equal number of atoms. After 200 minutes, the ratio of number of atoms of X unchanged to that of Y is
A
4
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B
2
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C
1/2
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D
1/4
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Solution
The correct option is B1/4 X ⇒ Initial amount of sample =x Half life =50 min After 200min i.e., 4 half lives, amount left unchanged =(12)4=(116) Y ⇒ Initial amount of sample =y Half life =100 min After 200min i.e., 2 half lives, amount left or unchanged =(12)2=14 So, ratio of XunchangedYunchanged=416=14