Two radioactive elements A and B (decay constant = 10λ and λrespectively), initially have the same number of nuclie. The ratio of nuclei of A and B left will be 1/e after time :
A
(10λ)−1
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B
(11λ)−1
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C
11×(10λ)−1
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D
(9λ)−1
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Solution
The correct option is D(9λ)−1 (No)B N=Noe−λt NANB=Noe−λAtNoe−λBt=e(λ−10λt) = e−9λt ∴e−9λt=1/e 9λt=1 ∴t=1/9λ