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Question

A and B are two radioactive elements having initial activity of10curieand20curie.If A has twice the number of moles as compared to B.Calculate the decay constant λAandλB.


A

10,5

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B

5,20

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C

20,10

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D

50,100

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Solution

The correct option is B

5,20


Explanation for the correct options:

B. 5,20

Step 1:

  • The activity of an element is defined as a number of nuclei that get decayed with time.
  • Activity is denoted by ‘A’.
  • A=-dNdT

Step 2:

  • Given,AA=10curies
  • AB=20curies
  • nA=2nB; let nB=x then nA=2x
  • dNdt=-λN=-dNdt×1N

Step 3:

  • For A=λA=10×12x=5x
  • For B=λB=20×1x=20x

Step4:

  • λA:λB=5:20

Hence,option(B)is correct,the decay constant λAandλB is 5,20.


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