Two radioactive elements X and Y have half-lives of 50 and 100 minute respectively. An initial sample of both the elements has same no. of atoms. The ratio of the remaining number of atoms of X and Y after 200 minutes is:
A
2
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B
1/2
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C
4
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D
1/4
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Solution
The correct option is D 1/4 As we know, N=N0/2n no. of particles after n half lives here, 200 minutes means 4 half life of X nad 2 half life of Y. AmountleftofX=N024∵n=4 (half-lives) AmountleftofY=N022∵n=2 ∴RatioofX:Yleft=2224=14