Question

Two Radioactive substances X and Y emit $\alpha$ and $\beta$ particles respectively. Their disintegration constants are in the ratio 2 : 3. To have equal rate of disintegration of getting emission of $\alpha$ and $\beta$ particles., the ratio of number of atoms of X to that of Y at any time instant is

• A. 2 : 3
• B. 3 : 2
• C. e : 1
• D. (e - 1) : 1

Answer 1

The correct option is B

3 : 2

Since, $\frac{{\lambda }_x}{{\lambda }_y}=\frac{2}{3}{N}_x{\lambda }_x=N_y{\lambda }_y\Rightarrow \frac{N_x}{N_y}=\frac{3}{2}$