Two rail tracks are $1 m$ apart and insulated from each other and insulated from ground. A milli-voltmeter is connected across the rail-tracks. When a train travelling at 180 $k m / h$ passes through what will be the reading in milli-voltmeter? Given : horizontal component of earth's field $\sqrt{3} \times 10^{- 4} T$ and dip at the place $60^{o}$ .

1.5 m V

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15 m V

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\frac{15}{\sqrt{3}} m V

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\frac{1.5}{\sqrt{3}} m V

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Solution

The correct option is A $15 m V$
Vertical component of the magnetic field will be $B_{v}$
$= B_{H} tan δ = 3 \times 10^{- 4} T$
Reading of mili voltmeter $= B_{v} I v = 3 \times 10^{- 4} \times 1 \times 50 = 15 m V$

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The correct option is A 15mVVertical component of the magnetic field will be Bv=BHtanδ=3×10−4TReading of mili voltmeter =BvIv=3×10−4×1×50=15mV

The correct option is A $15 m V$
Vertical component of the magnetic field will be $B_{v}$
$= B_{H} tan δ = 3 \times 10^{- 4} T$
Reading of mili voltmeter $= B_{v} I v = 3 \times 10^{- 4} \times 1 \times 50 = 15 m V$