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Question

Two reactions of the same order have equal exponential factors but their activation energies differ by 24.9kJ/mol. Calculate the ratio of the rate constants of this reaction at 27C. (R=8.314J K1mol1)


A
2.1×104
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B
2.1×103
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C
2.1
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D
None of these
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Solution

The correct option is A 2.1×104
We know that,
log10k=log10AE2.303RT

So, log10k2=log10AE22.303RT....eqn(1)

and log10k1=log10AE12.303RT.....eqn(2)

Substracting equation (2) from (1), we get,

log10(k2k1)=(E1E2)2.303RT

log10(k2k1)=24.9×10002.303×8.314×300

k2k1=2.14×104
Hence, (a) is correct.

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