Question

Two reactions proceed at ${25}^{o}C$ at the same rate; the temperatue coefficient of the rate of the first reaction is $2$ and that of the second reaction is $2.5$. Find the ratio of rate of these reactions at ${95}^{o}C$.

Answer 1

Temp. coefficient of a reaction in factor by which rate constant gets increased after every rise of $10°C$ in temperature.

At $25°$ both the reaction have same rate constants.

At $95°C$, for the reaction with rate with temperature coefficient $2$ is

$K_{95}=K_{25}\left(\frac{95-25}{10}\right)\times 2=14K_{25}$

And for the another reaction

${K^{\prime }}_{95}=K_{25}\left(\frac{95-25}{10}\right)\times 2.5=17.5K_{25}$

Hence, the ratio is

$\frac{14K_{25}}{17.5K_{25}}=\frac{28}{35}=\frac{4}{5}$