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Rate Constant

Two reactions...

Question

Two reactions $R_{1}$ and $R_{2}$ have identical pre-exponential factors. Activation energy of $R_{1}$ exceeds that of $R_{2}$ by $10 K j m o l^{- 1}$ If $K_{1}$ and $K_{2}$ are rate constants for reactions $R_{1}$ and $R_{2}$ respectively at $300 K$ , then in $(K_{2} / K_{1})$ is equal to: $(R = 8.314 j m o l^{- 1} K^{- 1})$

A

12

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B

6

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C

4

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D

8

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Solution

The correct option is C $4$

Option C is correct

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