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Question

Two reactions R1 and R2 have identical pre-exponential factors. Activation energy of R1 exceeds that of R2 by 10 kJmol1. If k1 and k2 are rate constants for reactions R1 and R2 respectively at 300 K, then ln(k2k1) is equal to :
(R = 8.314 Jmol1K1)

A
12
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B
6
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C
4
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D
8
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Solution

The correct option is C 4
k1=AeEa1RT

k2=AeEa2RT

k2k1=e(Ea2Ea1)RT

k2k1=e+10×1038.314×300

lnk2k1=4

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