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Question

Two real numbers α&β are such that α+β=3,αβ=4, then α&β are the roots of the quadratic equation:

A
4x212x7=0
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B
4x212x+7=0
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C
4x212x+25=0
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D
none of these
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Solution

The correct option is A 4x212x7=0
Given that,

α+β=3
αβ=4

By solving, we get
α=72 and β=12

The quadratic equation whose roots are α=72 and β=12 is

x2(α+β)x+αβ=0

x2(72+12)x+(72)(12)=0

x23x74=0

4x212x7=0

Option A is correct.

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