Two rectangular boxes have the same height and length, but different widths as shown in the figure.

If the difference in the volumes of the boxes is 360 cm $^{3}$ , then what is the height of the boxes?

18 cm

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15 cm

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16 cm

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14 cm

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Solution

The correct option is B
15 cm

Given, difference in the volumes of boxes = 360 cm $^{3}$
We know, volume of the box of dimension l×b×h = lbh
$∴ (12 \times 8 \times h) - (9 \times 8 \times h) = 360 \Rightarrow 24 h = 360 \Rightarrow h = 15 cm$

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Two rectangular boxes have the same height and length, but different widths as shown in the figure. If the difference in the volumes of the boxes is 360 cm3, then what is the height of the boxes?

The correct option is B 15 cm Given, difference in the volumes of boxes = 360 cm3 We know, volume of the box of dimension l×b×h = lbh ∴(12×8×h)−(9×8×h)=360⇒24h=360⇒h=15 cm

Two rectangular boxes have the same height and length, but different widths as shown in the figure.

If the difference in the volumes of the boxes is 360 cm $^{3}$ , then what is the height of the boxes?

The correct option is B
15 cm

Given, difference in the volumes of boxes = 360 cm $^{3}$
We know, volume of the box of dimension l×b×h = lbh
$∴ (12 \times 8 \times h) - (9 \times 8 \times h) = 360 \Rightarrow 24 h = 360 \Rightarrow h = 15 cm$