Two reservoirs are connected through a 930 m long. 0.3 m diameter pipe, which has a gate valve. The pipe entrance is sharp (loss coefficient = 0.5) and the valve is half-open (loss coefficient = 5.5). The head difference between the two reservoirs is 20 m. Assume the friction factor for the pipe as 0.03 and g=10 m/s2. The discharge in the pipe accounting for all minor and major losses is
L = 930 m
D = 0.3 m
Apply energy equation between A and B
20=0.5V22g+(0.03)(930)V22g(0.3)+5.5V22g+V22g
20=(0.03)(930)(0.3).V22g+7.0V22g
20=100V22g
V = 2 m/sec
Q=π4(0.3)2(2)
Q=0.1414 m3/sec