Two resistance at 0∘C with temperature coefficient of resistance α1 and α2 joined in series act as a single resistance in a circuit. The temperature coefficient of their single resistance will be
A
α1+α2
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B
α1α2α1+α2
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C
α1−α22
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D
α1+α22
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Solution
The correct option is Dα1+α22 R1=R0(1+α1t)+R0(1+α2t) =2R0(1+α1+α22t) Comparing with R=R0(1+αt) α=α1+α22.