Two resistance R1 and R2 are made of different materials- The temperature coefficient of the material of R1 is - and of the material of R2 is - The resistance of the series combination of R1 and R2 will not change with temp- then ratio of resistance of two wire will be -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Thermal Expansion

Two resistanc...

Question

Two resistance $R_{1}$ and $R_{2}$ are made of different materials. The temperature coefficient of the material of $R_{1}$ is $α$ and of the material of $R_{2}$ is $- β$ . The resistance of the series combination of $R_{1}$ and $R_{2}$ will not change with temp., then ratio of resistance of two wire will be :-

\frac{α}{β}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{α + β}{α - β}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{α^{2} + β^{2}}{α β}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{β}{α}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{β}{α}$
Here, $R_{1} + R_{2} =$ constant
When $R_{1}$ will increase, $R_{2}$ will decrease.
$d R_{1} + d R_{2} = 0$
or $R_{1} α Δ T - R_{2} β Δ T = 0$ as $[R = R_{0} (1 + α T)]$
or $\frac{R_{1}}{R_{2}} = \frac{β}{α}$

Suggest Corrections

Similar questions

Two resistance $R_{1}$ and $R_{2}$ are made of different materials. The temperature coefficient of the material of $R_{1}$ is $α$ and that of the material of $R_{2}$ is $β$ . The resistance of the series combination of $R_{2}$ and $R_{1}$ does not change with temperature, then the ratio of resistances of the two wires at $0^{o}$ will be:

Q. Two resistances

R_{1}

and

R_{2}

are made of different materials. The temperature coefficient of the material of

R_{1}

α

and that of material of

R_{2}

- β

. The material of

R_{1}

and

R_{2}

will not change with temperature if

\frac{R_{1}}{R_{2}}

equal to

If $R_{1}$ and $R_{2}$ are the resistance of a conductor at two temperatures $t_{1}^{0} C$ and $t_{2}^{0} C$ respectively, show that the temperature coefficient of resistance, $α = \frac{R_{2} - R_{1}}{R_{1} t_{2} - R_{2} t_{1}}$