Question

Two resistances $20\Omega$ and $40\Omega$ are connected in parallel. If total current is $4.5A$. Find the current through $20\Omega$ resistance

Answer 1

Since the resistances are in parallel , therefore the potential

difference (V = IR) across them is same .

Let the current across the 20 $\Omega$ and 40 $\Omega$ resistances be $i_1$ and $i_2$ respectively.

$i_1$ + $i_2$ = $4.5$ ...(i)

and $20i_1$ = $40i_2$ ...(ii)

From (i) and (ii) , we get

$i_1$ = $3A$ and $i_2$ = $1.5A$